Problem 1-66 |
Conversion factor:
1 µ = 1×10−6
1 ft = 0.3048 m
Volume of the room:
| Vroom = (18 ft × 12 ft × 8 ft) × | (0.3048 m)3 | = 48.9 m3 |
| (1 ft)3 |
mass of CO2 in 1 m3:
| Vroom = 400 000 µg.m−3 × | 1 g | = 0.4 g.m−3 |
| 1 000 000 µg |
Mass of CO2 in the room: = 48.9 m3 × 0.4 g.m−3 = 20 g.