Problem 4-11

Objective: make 150.0 mL of 0.10 mol/L NaCl

Therefore, you need to transfer a specific number of mole of NaCl in a volumetric flask of 150.0 mL.

n(NaCl) required = 150.0 mL × 0.10 mol/L = 15.0 mmol of NaCl

Knowing the number of mole NaCl required, you can calculate the volume of the 2.5 mol/L solution containing the same number of moles

15.0 mmol ×	1 L	= 6.0 mL
	2.5 mol

note: mmol = 1×10⁻³mol   same as mL = 1×10⁻³L.